MatchAllOffsets - cRegEx
Finds all matches and returns their start and end offsets in a two-dimensional array
Type: Function
Return Data Type: Integer[][]
Parameters
| Parameter | Type | Description |
|---|---|---|
| sSubject | String | The host string to run the regular expression on |
| bGroups | Boolean | If True. the array will contain both the full matches and the individual group matches |
Syntax
Function MatchAllOffsets String sSubject Boolean bGroups Returns Integer[][]
Call Example
Get MatchAllOffsets sSubject bGroups to Integer[][]Variable
Description
Finds all matches and returns their start and end offsets in a two-dimensional array.
Returns a two dimensional array with the start and end offsets of all matches found in the subject string. The offset positions are 1 based and position [0] is the start offset where [1] is the end offset. If bGroups is True, the array will contain both the full matches and the individual group matches; if bGroups is False, the array will contain only the full matches.
Sample
The example below shows how to find the offsets of matches in the subject string. The output of the sample should be "fun" and "lock".
Handle hoRegEx
Integer[][] aOffsets
String sSubject
Get Create (RefClass(cRegEx)) to hoRegEx
Set psExpression of hoRegEx to "fun|luck"
Move "This is no fun! This is luck!" to sSubject
Get MatchAllOffsets of hoRegEx sSubject False to aOffsets
Showln (Mid(sSubject, aOffsets[0][1] - aOffsets[0][0], aOffsets[0][0]))
Showln (Mid(sSubject, aOffsets[1][1] - aOffsets[1][0], aOffsets[1][0]))
Send Destroy of hoRegEx
Return Value
Two-dimensional array of the full matches (if bGroups is True) and start and end offsets of all matches.